Question

The external radius and the length of a hollow wooden log are 16cm and 13cm respectively.If its thickness is 4cm then find its T.S.A


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Answer 1

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Answer 2

TSA of given Cylinder is  $2992\:cm^2$

Given :

External radius of cylinder (R) = 16cm

Height of the cylinder (h) = 13cm

Thickness of cylinder (t) = 4cm

To Find :

T.S.A of cylinder

Formula Applied :

TSA of cylinder = $2\pi (R+r)(R -r +h)$

Solution :

Thickness of cylinder = External Radius - Internal Radius

$\implies t =R -r$

$\implies 4 =16-r$

$\implies r = 16-4$

$\boxed{r=12cm}$

$\text{T.S.A of Cylinder = }$ $2\pi (R+r)(R-r+h)$

$\implies 2 \times \frac{22}{7}(16+12)(16-12+13)$

$\implies \frac{44}{7}(28)(4+14)$

$\implies 44 \times 4 \times 17$

$\boxed{\text{TSA of cylinder }=2992 \: cm^2}$