The external radius of a hollow right circular cylindrical pipe is 9cm and its height is 14cm. The volume of the metal used to make the pipe is 748cm3. Find the thickness of the pipe
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dimensions of a pipe are:-
Height =h=14cm
Radius = r.cm
Given,
Volume =748 cm³
π*r²*h=748
22/7*r²*h=748
r² =(748*7)/(22*14)
r²=17
r = root 17
r = 4(approx.)
external radius R= 9cm (given)
Thickness of the pipe =9 - 4
=5cm
Height =h=14cm
Radius = r.cm
Given,
Volume =748 cm³
π*r²*h=748
22/7*r²*h=748
r² =(748*7)/(22*14)
r²=17
r = root 17
r = 4(approx.)
external radius R= 9cm (given)
Thickness of the pipe =9 - 4
=5cm
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