The external radius of a hollow right circular cylindrical pipe is 9cm and its height is 14cm.The volume of the metal used to make the pipe is 748 cm².Find the thickness of the pipe.
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external radius of pipe= 9
height of pipe = 14
volume of pipe = 748
volume of pipe = πh(Rsq-rsq)
748 = 22÷7×14(9×9-rsq)
748 = 22×2(81-rsq)
748= 44(81-rsq)
748= 3564-44rsq
44rsq = 3564-748
44rsq= 2816
rsq= 2816÷44
rsq = 64
r = √64
r = 8
thickness of pipe = R-r
= 9-8
= 1
height of pipe = 14
volume of pipe = 748
volume of pipe = πh(Rsq-rsq)
748 = 22÷7×14(9×9-rsq)
748 = 22×2(81-rsq)
748= 44(81-rsq)
748= 3564-44rsq
44rsq = 3564-748
44rsq= 2816
rsq= 2816÷44
rsq = 64
r = √64
r = 8
thickness of pipe = R-r
= 9-8
= 1
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