Physics, asked by akshaykapilan2005, 1 month ago

The external work required to slowly rotate a dipole of dipole moment 1C-m in uniform electric field of magnitude 20 V/m from stable equilibrium state to unstable equilibrium state is​

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Answered by khushisharma4508
0

Answer:

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Explanation:

P=3×10−8Cm;E=104N/C

At stable equilibrium (θ1)=0∘

At unstable equilibrium (θ2)=180∘

Work done in a rotating dipole is given by:

W=PE(cosθ1−cosθ2)=(3×10−8)(104)[cos0∘−cos180∘]=3×10−4[1−(−1)]

W=6×10−4J.

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