Question

The extremities of the base of an isosceles triangle abc are the points a(2,0) and b(0,1). if the equation of the sides ac is x=2 then the slope of the side bc is

Answer 1

heya....


equation of side ac is x=2,

so the point c has coordinates (2,k) and also distance between points a and c is equal to points b and c(since isosceles),

so (k=5/2)

and using slope formula slope of bc is 3/4


tysm.#gozmit

Answer 2

Let C(2,y)
by distance formula
CB = CA
square
CB^2 = CA^2
(2-0)^2 + (y-1)^2 = (2-2)^2 + (y-0)^2
4 + y^2 - 2y +1 = y^2
5 = 2y
y = 5/2

so C(2,5/2)

slope of the side bc is using slope formula
= (y2 - y1)/(x2-x1)
= (5/2 - 1)/(2-0)
= 3/4 ans