The eyes of a certain member of the reptile family pass a single visual single to the brain when the visual receptors are stuck by photons of wavelength 662.6 nm. If a total energy of 3.01*10^14 J is required to trap the signal, what is the minimum number of photons that must strike the receptor ?
(1) 1.0*10^5 (2) 1.0*10^6 (3) 1000 (4) 1
Answers
Answered by
3
energy of each photon=h×3×10^8/(662.6×10^-9)
=(6.6×10^-34×10^8×3)/(662.6×10^-9)
=10^(8+11+-34)×3
=3×10^-15
total photos required=total energy required/energy of 1 photon=3 .01×10^14/3×10^-15
=1×10^19(approx)
=1
hence option 4✓✓✓
Answered by
9
Answer:
hey did you remember Adi class 11 wala...??....im that guy....follow back✌
Similar questions