Math, asked by 3090546, 20 days ago

The face of a clock has a circumference of 63 in. What is the area of the face of the clock? (Hint: 1st - Find diameter by using d = C ➗ , then find the radius by using r = d ➗ 2, last find area using A = r2)

Answers

Answered by gyanendrakumaru
1

answer:-As we know that circumference of the circle is given as-

Circumference =2πr

Given:-

Circumference of the circle =31.4cm

∴2πr=31.4

⇒2×3.14×r=31.4

⇒r=5cm

Now again as we know that the area of the circle is given as-

Area =πr

2

⇒ Area =3.14×(25)

2

=78.5cm

2

Hence the radius and area of the circle is 5cm amd 78.5cm

2

respectively.

Answered by preeti353615
1

Answer:

If the face of a clock has a circumference of 63 in then the area of the face of the clock is 315.715 sq. in 315.715 sq. in.

Step-by-step explanation:

Given: The circumference of the clock = 63 inch.

Find : The area of the face of the clock.

Formula:

Area of circle = \pi r^2

The circumference of circle = 2\pi r

2 \times \frac{22}{7}  \times r = 63\\ \frac{44}{7}  \times r = 63\\    r = 63 \times \frac{7}{44} \\r = \frac{441}{44}

Now find the area of the circle

\pi r^ = \frac{22}{7} \times (\frac{441}{44} )^2\\= \frac{22}{7} \times \frac{441}{44}    \times \frac{441}{44}   \\= 315.715 sq. in.

Similar questions