Question

The face value of ones place digit is 3 and tens place digit is 7.write the number.​

Answer 1

Answer:

The sum of the digits of a two digit number is 8 and the difference between the number and that formed by reversing the digits is 18. Find the number.

MEDIUM

Step-by-step explanation:

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10th

Maths

Pair of Linear Equations in Two Variables

Algebraic Solution of a Pair of Linear Equations

ANSWER

Let x be the digit at unit’s place and y be the digit at ten’s place.

Since y is at ten’s place, then the number formed is 10y+x.

By reversing the digits, it becomes 10x+y.

As the difference of the numbers is 18, so,

(10y+x)−(10x+y)=18

9(y−x)=18

y−x=2 .... (1)

As the sum of digits is 8, so,

x+y=8 .... (2)

On adding equations (1) and (2), we get

2y=10⇒y=5

Putting this in (2), we get x=8−5=3

x=3,y=5

Hence, number =10y+x=10×5+3=53