Math, asked by nsmviie38srilaasya, 6 months ago

the faces of 2 dices are marked 1,2,3,4,5,6 and -1,-2,-3,-4,-5,-6 respectively. if the player gets a score of 20 first is the winner, what is the minimum number of throws required to win the match ​

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Answered by rjanjal0070
1

Answer:

The faces of two dice are marked +1, +2, +3, +4, +5, +6 and-1,-2, -3, -4,-5,-6, respectively. Two players throw the pair of dice altermately and record the sum of the numbers that turn up cach time and keep adding their scores separately. The player who's score reaches 20 or more first, wins the game. (a) What can be the possible maximum score in a single throw of the pair of dice? (b) What can be the possible minimum score in a single throw of the pair of dice?

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