Question

the faces of a die bear numbers 0 ,1 ,2, 3 ,4 ,5 if the die is rolled twice then find the probability that the product of digits on the upper face is zero​

Answer 1

so the favourable events are

(0,0),(0,1),(0,2),(0,3),(0,4),(0,5),(1,0),(2,0),(3,0),(4,0)and(5,0)

total outcomes =6^2 =36

probability= 11/36