Question

The faces of a die bear the numbers 1,3,5,7,9,11. The die is rolled.
Find the probability of getting a perfect square number on the upper face
of the dice.

Answer 1

Hlw Dude !

$\bf\bigstar{QUESTION}$

The faces of a dice bear the numbers 1,3,5,7,9,11. The die is rolled.

Find the probability of getting a perfect square number on the

upper face  of the dice.

$\bf\bigstar{ANSWER}$

The given outputs :-

                    1,3,5,7,9,11.

Total no of outcomes :- 6

According to the given condition,

Possible outcomes :- 1 & 9.

1 = 1 x 1

9 = 3 x 3

These are the perfect squares we have here !

Then the probability of getting a perfect square in its face =

$\huge{\boxed{\bf{\frac{Possible\:outcomes}{Total\:no.\:of\:outcomes}}}}}}$

⇒                        $\huge{\boxed{\boxed{\boxed{\bf{\frac{2}{6}}}}}$

  ⇒                        $\huge{\boxed{\bf{\bf{\frac{2}{6}= \bf{\frac{1}{3}}}}}$

Hope this answer can helps!!