Question

The factor form of (a4 b4-16c4)

Answer 1

Solution :

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We know the algebraic identity'

x² - y² = ( x + y )( x - y )

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Here ,

a⁴b⁴ - 16c⁴

= ( a²b² )² - ( 2²c² )²

= ( a²b² + 2²c² )( a²b² - 2²c² )

= (a²b²+4c²)[ (ab)² - ( 2c )² ]

= (a²b²+4c²)( ab + 2c )( ab - 2c )

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