The factor form of (a4 b4-16c4)
KhushbooGoutam:
and you tell me about you
please
oh really
I am in 8th class
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Solution :
***************************************
We know the algebraic identity'
x² - y² = ( x + y )( x - y )
***************************************
Here ,
a⁴b⁴ - 16c⁴
= ( a²b² )² - ( 2²c² )²
= ( a²b² + 2²c² )( a²b² - 2²c² )
= (a²b²+4c²)[ (ab)² - ( 2c )² ]
= (a²b²+4c²)( ab + 2c )( ab - 2c )
••••••
***************************************
We know the algebraic identity'
x² - y² = ( x + y )( x - y )
***************************************
Here ,
a⁴b⁴ - 16c⁴
= ( a²b² )² - ( 2²c² )²
= ( a²b² + 2²c² )( a²b² - 2²c² )
= (a²b²+4c²)[ (ab)² - ( 2c )² ]
= (a²b²+4c²)( ab + 2c )( ab - 2c )
••••••
oh really
but why
I am so sorry
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