Math, asked by bhoomika200511, 1 year ago

the factor of 1/12- x^2/48 are​

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Answered by rehanjalees
2

Answer:

Step-by-step explanation:

1/12 -x^2/48

= 1/12[1 - x^2/4] Take 1/12 common

=1/12 [(1)^ - (x/2)^2]. a^2 - b^2 = (a-b)(a+b)

= 1/12[(1-x/2)(1+x/2)]

Answered by prabhjotk20062
0

Step-by-step explanation:

multi choice answer

hope will help

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