the factor of 1 by 3 x square - 2 x minus 9 is equal to
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Answered by
41
Heya !!!
1/3 X² - 2X - 9 = 0
=> X²/3 - 2X -9 = 0
=> X²-6X-27X/3 = 0
=> X²-6X-27 = 0 × 3
=> X²-6X-27 = 0
=> X²-9X +3X -27 = 0
=> X(X-9) +3(X-9) = 0
=> (X-9) (X+3) = 0
Hence,
(X-9) and (X+3) are two factor of Polynomial X²/3 - 2X -9.
HOPE IT WILL HELP YOU....... :-)
1/3 X² - 2X - 9 = 0
=> X²/3 - 2X -9 = 0
=> X²-6X-27X/3 = 0
=> X²-6X-27 = 0 × 3
=> X²-6X-27 = 0
=> X²-9X +3X -27 = 0
=> X(X-9) +3(X-9) = 0
=> (X-9) (X+3) = 0
Hence,
(X-9) and (X+3) are two factor of Polynomial X²/3 - 2X -9.
HOPE IT WILL HELP YOU....... :-)
shruti2310:
koi toh follow karo
Answered by
34
x²/3 - 2x - 9
=> (x² - 6x - 27)/3
=> [ x² - (9 - 3)x - 27] /3
=> [ x² - 9x + 3x - 27] /3
=> [ x(x - 9) + 3(x - 9)] /3
=> [ (x - 9)(x + 3)] /3
(x - 9)/3 and (x + 3)/3 are the factors
I hope this will help you
(-:
=> (x² - 6x - 27)/3
=> [ x² - (9 - 3)x - 27] /3
=> [ x² - 9x + 3x - 27] /3
=> [ x(x - 9) + 3(x - 9)] /3
=> [ (x - 9)(x + 3)] /3
(x - 9)/3 and (x + 3)/3 are the factors
I hope this will help you
(-:
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