the factor of 4x^2+4x-3 are
1- (2x-1)(2x+3)
2-(2x+1)(2x+3)
3-(2x+1)(2x-3)
4-none
Answers
Answer:
(2x - 1) * (2x + 3)
Step-by-step explanation:
4x2+4x-3
Final result :
(2x - 1) * (2x + 3)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(22x2 + 4x) - 3
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 4x2+4x-3
The first term is, 4x2 its coefficient is 4 .
The middle term is, +4x its coefficient is 4 .
The last term, "the constant", is -3
Step-1 : Multiply the coefficient of the first term by the constant 4 • -3 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is 4 .
-12 + 1 = -11
-6 + 2 = -4
-4 + 3 = -1
-3 + 4 = 1
-2 + 6 = 4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 6
4x2 - 2x + 6x - 3
Step-4 : Add up the first 2 terms, pulling out like factors :
2x • (2x-1)
Add up the last 2 terms, pulling out common factors :
3 • (2x-1)
Step-5 : Add up the four terms of step 4 :
(2x+3) • (2x-1)
Which is the desired factorization
Final result :
(2x - 1) * (2x + 3)
option 3is correct (2x+1)(2x-3)