Math, asked by adarsh292, 1 year ago

the factor of 6-y-2y^2

Answers

Answered by Anonymous

$\underline{\large\bf{\mathfrak{Hello!}}}$

$= > 6 - y - 2 {y}^{2} \\ \\ = > 6 - 4y + 3y - 2 {y}^{2} \\ \\ = > 2(3 - 2y) + y(3 - 2y) \\ \\ = > (3 - 2y)(2 + y)$

$\boxed{Factors \: of \: (6 - {y} - 2{y}^{2}) = (3 - 2{y}) \: {and} \: (2 + {y})}$

$\bf{\mathfrak{Hope \: this \: helps...:)}}$

adarsh292: thanks but the answer is -2y+3. try again

Anonymous: -2y + 3 is same as 3 - 2y

adarsh292: I know but your answer is (3-y)(2+y)

Anonymous: No, my answer is (3 - 2y)(2 + y)

adarsh292: yeah I am sorry

adarsh292: but answer is -2y+3

adarsh292: it was not same as (3-2y)(2+y)

Anonymous: There might be misprint in answer

adarsh292: no it was not misprint, I am sure about the answer

Anonymous: But -2y + 3 and 2 + y both are the factors of the given equation

Answered by TRISHNADEVI

✍✍HERE IS YOUR ANSWER..⬇⬇
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$\underline{SOLUTION}$ ➡

$6 - y - 2y {}^{2} \\ \\ = 6 - (4 - 3)y - 2y {}^{2} \\ \\ = 6 - 4y + 3y - 2y {}^{2} \\ \\ = 2(3 - 2y) + y(3 - 2y) \\ \\ = (2 + y)(3 - 2y)$

$So ,\: \: \\ \\ Factor \: \: of \: \: 6 - y - 2y {}^{2} = (2 + y)(3 - 2y)$

$\underline{ANSWER}$ ➡

$\boxed{6 - y- 2y {}^{2} = (2 + y)(3 - 2y)}$

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✝✝…HOPE…IT…HELPS…YOU…✝✝

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