Question

the factor of 8 x cube + 64 y cube​

Answer 1

solution

8x³ + 64y3

(2x)³ + (4y)³

by using identity

a³ + b³= (a+b) ( a² + b² - ab )

so, ( 2x + 4y ) (2x² + 4y² - 2x4y)

Answer 2

Answer:

8(x+2y)(x^2+2xy+4y^2)

Step-by-step explanation:

8x^3+64y^3

=8(x^3+8y^3)

=8{x^3+(2y)^3}

=8(x+2y){x^2+x×2y+(2y)^2}

[a^3+b^3=(a+b)(a^2+ab+b^2)]

=8(x+2y)(x^2+2xy+4y^2)

(^2 means square and ^3 means cube)