Question

the factor of p(y) =y square -y-12 are
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Answer 1

Answer:

4

Step-by-step explanation:

$let \: y \: be \: 4 \\ {y}^{2} - y - 12 = 16 - 4 - 12 = 0$

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Answer 2

Answer:

p(y) = y square -(4-3)y -12

= y square-4y+3y -12

= y(y-4) +3 (y-4)

= (y+3) (y-4)

y =-3 , 4