Chemistry, asked by piyushpiyu4557, 1 year ago

The factor of \Delta G values is important in metallurgy. The \Delta G values for the following reactions at 800ºC are given as :
S_2(s) + 2O_2(g) \longrightarrow 2SO_2(g); \Delta G = – 544 kJ
2Zn(s) + S_2(s) \longrightarrow 2ZnS(s); \Delta G = – 293 kJ
2Zn(s) + O_2(g) \longrightarrow 2ZnO(s); \Delta G = – 480 kJ
Then \Delta G for the reaction :
2ZnS(s) + 3O_2(g) \longrightarrow 2ZnO(s) + 2SO_2(g)
will be :
(a) –357 kJ
(b) –731 kJ
(c) –773 kJ
(d) –229 kJ

Answers

Answered by purvi200428
0

(a) part is the correct option

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