Question

the factor of the following algebraic expression is 16ab2c​

Answer 1

Answer:

8b4a4c

Step-by-step explanation:

Firstly, 3 and 12 have a common factor of 3.

So we could have:

3y2+12y = 3(y2+4y)

But we can do better!

3y2 and 12y also share the variable y.

Together that makes 3y:

3y2 is 3y × y

12y is 3y × 4

 

So we can factor the whole expression into:

3y2+12y = 3y(y+4)

 

Check: 3y(y+4) = 3y × y + 3y × 4 = 3y2+12y