Question

The factorisation of 64a³b³ ─ 27 is:​

Answer 1

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$\sf 64 {a}^{3} {b}^{3} - 27$

$\sf = {(4ab)}^{3} - {3}^{3}$

$\sf = (4ab - 3)(16 {a}^{2} {b}^{2} + 12ab + 9)$

Answer 2

$(4ab-3)(16{a}^{2} +9+12 {ab}^{2} )$

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