Question

The factorisation of 64p² – 81q² involves :

a) (a + b)² = a² + 2ab + b²

b) (a – b)² = a² – 2ab + b²

c) (a + b)(a – b) = a² + b²

d) None of these

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Answer 1

Answer:

the correct answer is option c

that is the only suitable identity

Answer 2

Answer:

Answer- none of these

identity- (a²-b²)

=(a+b)(a-b)