Question

The factorisation of 64p² – 81q² involves :

a) (a + b)² = a² + 2ab + b²

b) (a – b)² = a² – 2ab + b²

c) (a + b)(a – b) = a² + b²

d) None of these​

Answer 1

Answer:

D. None of these

64p²-81q²

(8p)²-(9q)²

(8p+9q)(8p-9q)

a²-b²=(a+b)(a-b)

Step-by-step explanation:

Hope it helps.....

Answer 2

Answer:

$(a - b)^{2} = a ^{2} - 2ab + b^{2}$