Math, asked by bigboy690, 2 months ago

The factorisation of am2+ bm2+ bn2+ an2is

Answers

Answered by YeshaTrivedi
1

Answer:

(m²+n²)(a+b)

Step-by-step explanation:

am²+bm²+bn²+an²

"Taking out m² common from both am²and bm² and n² from bn²and an²"

m²(a+b) +n²(a+b)

m²+n²(a+b)

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