The factorisation of am2+ bm2+ bn2+ an2is
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Answer:
(m²+n²)(a+b)
Step-by-step explanation:
am²+bm²+bn²+an²
"Taking out m² common from both am²and bm² and n² from bn²and an²"
m²(a+b) +n²(a+b)
m²+n²(a+b)
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