The factorisation of (lm + l) + m + 1 is
(a) (l + 1)(m + 1)
(6) (l – 1)(m – 1)
(c) (l + 1)(m – 1)
(d) (l – 1)(m + 1).
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(lm+1) +m +1
l ( m+1 ) +1 ( m+1 )
( l+1 ) ( m+1 )
Answer A is correct
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1
Answer:
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