the factorisation of p2 -9q2
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Answer:
Answer:
p²-10p+25 = (p-5)(p-5)
Step-by-step explanation:
Given quadratic expression:
p²-10p+25
Method 1:
p² - 10p + 25
= p²-2×p×5 + 5²
= (p-5)²
/* By algebraic identity:
\boxed {a^{2}-2ab+b^{2}=(a-b)^{2}}
a
2
−2ab+b
2
=(a−b)
2
*/
=(p-5)(p-5)
Therefore,
p²-10p-25 = (p-5)(p-5)
Method 2:
p²-10p-25
Splitting the middle term, we get
=p²-5p-5p-25
= p(p-5)-5(p-5)
= (p-5)(p-5)
Therefore,
p²-10p+25 = (p-5)(p-5)
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