The factorisation of Z²-4z-12 is *
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Step-by-step explanation:
Z²-4z-12 = {Z²-2.Z.2+2²}-2²-12
=(Z-2)²-16
= (Z-2)²-4²
= {(Z-2)+4} {(Z-2)-4}
=(Z+2)(Z-6). (Ans)
Note: Using identity (a+b)(a-b) = a²-b²
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