Question

The factorise 3x^2 + 10x + 8 ​

Answer 1

Answer:

Now we have to find out the pair of integers whose product is equal to $ - 24$ and sum is equal to $10$. In that case the required pair is $\left( {12, - 2} \right)$. Hence, the factors of the given equation $3{x^2} + 10x - 8 = 0$ are $\left( {3x - 2} \right)\left( {x + 4} \right) = 0$.