The factorization of a2-9a+18
adarshgupta9666:
IT IS a^2
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1 (a2-9a+18)
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Answer:
a^2 - 9a + 18 =0
a^2 -6a -3a +18 =0
a(a - 6) -3 ( a - 6) =0
( a -6 ) ( a - 3) =0
a-6 =0 , a-3=0
a=6 ,a=3 you
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Step-by-step explanation:
a^2 - 9a + 18
a^2 -6a -3a +18
a(a - 6) -3 ( a - 6)
( a -6 ) ( a - 3)
a^2 -6a -3a +18
a(a - 6) -3 ( a - 6)
( a -6 ) ( a - 3)
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