Question

the factorization of cube(x)-3*square(x)-9x-5 is (x+1)(x+1)(x-5)​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

x^3-3x^2-9x-5

=x ^3+x^2 -4x^2-4x-5x-5

= x^2 (x+1)-4x (x+1)-5 (x+1)

=(x+1)(x^2-4x-5)