Math, asked by prateekmtripathi840, 7 months ago

The factors of ( 1 – 6 z+ 9 z2  )are

Answers

Answered by Kanagaraju
1

Answer:

= (1 - 3z) × (1 -3z)

Step-by-step explanation:

1 - 6z + 9z^2 = ( 1 - 3z)^2 = (1 -3z) × (1 - 3z)

Answered by Anonymous
0

Answer:

=> 1 - 6z + 9z^2

=> ( 1 - 3z)^2

=> ( 1 - 3z ) ( 1 - 3z )

Step-by-step explanation:

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