The factors of ( 1 – 6 z+ 9 z²
)are
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Factors are (3z-1)(3z-1)
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Answer:
product of 1 and 9=9
factors of 9 that add up to -6= -3 and -3
1-3z-3z+9zsquare
1(1-3z) - 3z(1-3z)
(1-3z)(1-3z)
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