Question

The factors of 13x^2 z are

Answer 1

Step-by-step explanation:

Let p(x)=x

3

−2x

2

−13x−10

By trail, we find that p(−1)=(−1)

3

−2(−1)

2

−13(−1)−10=−1−2+13−10=0. So (x+1) is factor of p(x).

Now, x

3

−2x

2

−13x−10=x

3

+(x

2

−3x

2

)−(3x+10x)−10

=(x

3

+x

2

)−(3x

2

+3x)−(10x+10)

=x

2

(x+1)−3x(x+1)−10(x+1)

=(x+1)(x

2

−3x−10)

=(x+1)[x

2

−5x+2x−10]

=(x+1)[x(x−5)+2(x−5)]

=(x+1)(x−5)(x+2)

=(x−5)(x+1)(x+2)

Option D is correct