Math, asked by sneha1777450, 3 months ago

the factors of 2πrh-2πr²-πh+πr

Answers

Answered by GaneshRM2006
2

Answer:

2πrh-2πr²-πh+πr

=2πrh-πh-2πr²+πr

=πh(2r-1)-πr(2r-1)

=(πh-πr)(2r-1)

Answered by Srihitha007
1

Answer:

I don't know actually I know but first to solve it read the question

Step-by-step explanation:

so,

1. arrange the following equations in order.

2.then take the terms in common.

3.factors will be ( πh-πr) (2r-1)

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