the factors of 2 x square - 7 x + 3
pratibhaR001:
x-3 nd 2x-1
Answers
Answered by
4
Here is your answer:
2x² - 7x + 3
⇒ 2x² - 6x - x + 3
⇒ 2x ( x - 3 ) - 1 ( x - 3 )
⇒ (x - 3)(2x - 1)
The factors are 3 and ½.
Answered by
1
2x² - 7x + 3 = 0
2x² - 6x - x + 3 = 0
2x(x - 3) -1(x - 3) = 0
(x - 3) (2x - 1) = 0
x = 3, 1/2
Thankyou!!!
2x² - 6x - x + 3 = 0
2x(x - 3) -1(x - 3) = 0
(x - 3) (2x - 1) = 0
x = 3, 1/2
Thankyou!!!
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