Question

the factors of 20^x(3/2)^2x=81/16
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Answer 1

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

0-(2*x^4+x^3-24*x^2+20*x+16)=0

Step by step solution :

STEP

1

:

Equation at the end of step 1

0-(((((2•(x4))+(x3))-(23•3x2))+20x)+16) = 0

STEP

2

:

Equation at the end of step

2

:

0 - ((((2x4 + x3) - (23•3x2)) + 20x) + 16) = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

-2x4 - x3 + 24x2 - 20x - 16 =

-1 • (2x4 + x3 - 24x2 + 20x + 16)

Polynomial Roots Calculator :

4.2 Find roots (zeroes) of : F(x) = 2x4 + x3 - 24x2 + 20x + 16

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0