the factors of 2x²-7x+3 are
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1
Answer:
6 and -1...
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Answer:
2x²–7x+3=0 (if x is a root)
=>2x²–6x–x+3=0
=>2x(x–3)–1(x–3)=0
=>(2x–1)(x–3)=0
Therefore, either, 2x–1=0 or x–3=0
=>x=1/2 or x=3
Its roots are 1/2 and 3
Its factors are (2x–1)(x–3)
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