Math, asked by nchat16, 9 months ago

The factors of 32 - 2 ( x-4 ) ( x-4 ) is

Answers

Answered by siddhusujhatha
0

Answer:The number 32 is a composite and it should have prime factors. Now let us know how to calculate the prime factors of 32.

Step 1: The first step is to divide the number 32 with the smallest prime factor, say 2.

32 ÷ 2 = 16

Step 2: Again divide 16 by 2 and the process goes on.

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

2 ÷ 2 = 1

Finally, we received the number 1 at the end of the division process. So that we cannot proceed further. So, the prime factors of 32 are written as 2 × 2 x 2 x 2 x 2 or 25, where 2 is a prime numbers.

It is possible to find the exact number of factors of a number with the help of prime factorisation. The prime factor of the 32 is 25. The exponent in the prime factorisation is 5. When you add the number 1 with the exponent, we get 6. i.e.,5 +1 = 6. Therefore, the number 32 has 6 factors.

Step-by-step explanation:

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