The factors of 4 y²-12 y +g is
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Answer:
Method 1:-
= > 4 {y}^{2} + 9 - 12y=>4y
2
+9−12y
= > 4 {y}^{2} - 12y + 9=>4y
2
−12y+9
Factorize it by the middle term technique/Splitting middle term technique.
= > 4 {y}^{2} - 6y - 6y + 9=>4y
2
−6y−6y+9
= > 2y(2y - 3) - 3(2y - 3)=>2y(2y−3)−3(2y−3)
= > (2y - 3)(2y - 3)=>(2y−3)(2y−3)
= > (2y - 3) {}^{2}=>(2y−3)
2
Method 2:-
=4y²+9-12y
=(2y)²+3²-2×2y×3
=(2y-3)²
I used (a-b)²=a²+b²-2ab
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