Math, asked by KyaKarogeNamJankar, 2 months ago

The factors of 4 y²-12 y +g is​

Answers

Answered by goudshaker232
1

Answer:

Method 1:-

= > 4 {y}^{2} + 9 - 12y=>4y

2

+9−12y

= > 4 {y}^{2} - 12y + 9=>4y

2

−12y+9

Factorize it by the middle term technique/Splitting middle term technique.

= > 4 {y}^{2} - 6y - 6y + 9=>4y

2

−6y−6y+9

= > 2y(2y - 3) - 3(2y - 3)=>2y(2y−3)−3(2y−3)

= > (2y - 3)(2y - 3)=>(2y−3)(2y−3)

= > (2y - 3) {}^{2}=>(2y−3)

2

Method 2:-

=4y²+9-12y

=(2y)²+3²-2×2y×3

=(2y-3)²

I used (a-b)²=a²+b²-2ab

Answered by rashmibordoloi288
0

Answer:

bbznznznnaa

skkskalak

Step-by-step explanation:

jKakkakaksk

smakkakak

skakkakakak

aamakallakwlw

Similar questions