Question

The factors of 4x^2 – 9a^2 + 6ab – b^2 are pls help me​

Answer 1

Answer:

(4c+3a+b)(4c-3a-b)

Step-by-step explanation:

16c² - 9a² - 6ab - b²

→ (4c)² - [ (3a)²+ 2×3a×b + (b)² ]                  ......by using (a+b)² identities

∴ (4c)² - (3a+b)²

Now by using "a² - b²" identities we get,

⇒ (4c+3a+b)(4c-3a-b)

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