Math, asked by alberteinstien7677, 8 months ago

The factors of 4y2 - 12y + 9 is

Answers

Answered by rhythm46
12

Answer:

4y^2 - 12y + 9 = 0

4y^2 - 6y - 6y + 9 = 0

2y(2y-3) - 3(2y-3) = 0

(2y-3) (2y-3) = 0

y = 3/2 y = 3/2

The factor is y=3/2

Answered by Jai0917
8
4y^2 - 12y +9
4y^2 - 6y - 6y + 9
2y(2y-3)-3(2y-3)
=(2y-3)(2y-3)
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