Question

The factors of 7y power2-19y-6 are

Answer 1

Step-by-step explanation:

Factoring 7y2-19y-6

The first term is, 7y2 its coefficient is 7 .

The middle term is, -19y its coefficient is -19 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 7 • -6 = -42

Step-2 : Find two factors of -42 whose sum equals the coefficient of the middle term, which is -19 .

-42 + 1 = -41

-21 + 2 = -19 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -21 and 2

7y2 - 21y + 2y - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

7y • (y-3)

Add up the last 2 terms, pulling out common factors :

2 • (y-3)

Step-5 : Add up the four terms of step 4 :

(7y+2) • (y-3)

Which is the desired factorization