Question

The factors of 8a²+b³-6ab+1are
A. (2a+b-1)(4a²+b²+1-3ab-2a)
B. (2a-b+1)(4a²+b²-4ab+1-2a+b)
C. (2a+b+1)(4a²+b²+1-2ab-b-2a)
D. (2a-1+b)(4a²+1-4a-b-2ab)

Answer 1

Answer:

THE CORRECT ANSWER IS OPTION B.

HOPE THIS HELPS.

PLEASE FOLLOW ME AND MARK ME AS THE BRAINLIEST ANSWER.

Answer 2

Step-by-step explanation:

(2a-b+1)(4a²+b²-4ab+1-2a+b) :ans

explanation :-

split the equation into two parts

like:- (2a-b+1)(4a²+b²-4ab+1-2a+b)

here 2a×4a² and above is also like this