Question

the factors of 9x²-22xy+8y²

Answer 1

9xsqr-18xy-4xy+8ysqr
= 9x(x-2y)-4y(x-2y)
= (9x-4y)(x-2y)

Answer 2

Answer :

Now,

9x² - 22xy + 8y²

= 9x² - ( 18 + 4 ) xy + 8y²,

since 9 × 8 = 72 = 18 × 4 and 22 = 18 + 4

= 9x² - 18xy - 4xy + 8y²

= 9x ( x - 2y ) - 4y ( x - 2y )

= ( x - 2y ) ( 9x - 4y ),

which is the required factorization.

Hence, ( x - 2y ) and ( 9x - 4y ) are the factors of the given quadratic polynomial.

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