Question

The factors of m² + 6m + 9 are​

Answer 1

• As per the data given in the question, we have to find the value of the expression.

            Given data:- $m^{2} +6m+9.$

            To find:- Value of the expression.

            Solution:-

• method of breaking the arithmetic algebraic expressions into the product of their factors is called a factor.

           Therefore,

              $m^{2} +6m+9\\=m^{2}+3 m+3 m+9\\=m(m+3)+3(m+3)\\=(m+3)(m+3)\\=(m+3)^{2}.$

   Hence we will get the factor  $m^{2} +6m+9=(m+3)^{2} .$

Answer 2

Given: The equation is$m^{2} +6m+9$.

We have to find the factors of the above equation.

As we know that the method of breaking the arithmetic algebraic expressions into the product of their factors is called a factor.

By using this method, we are finding the factors of the above equation.

We are solving in the following way:

We have,

$\begin{array}{l}m^{2}+6 m+9 \\=>m^{2}+3 m+3 m+9 \\=>m(m+3)+3(m+3) \\=>(m+3)(m+3) \\\\\end{array}$

Solving the above equation further we get,

$=>m=-3;m=-3$

Hence, the factors of the above equation will be$-3 and -3$.