Question

The factors of
$(2a - b) {3} + (b - 2c)3 + 8(c - a) \:$
is:​

Answer 1

Answer:

a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

So, if a+b+c=0, a

3

+b

3

+c

3

=3abc

The given expression can be written as

(2a−b)

3

+(b−2c)

3

+(2c−2a)

3

We can see here that 2a−b+b−2c+2c−2a=0.

Hence, following the above concept

(2a−b)

3

+(b−2c)

3

+(2c−2a)

3

=6(2a−b)(b−2c)(c−a)

I hope this thankful

Answer 2

Step-by-step explanation:

2c-2a or 2(c-a). is right answer

solve it by simple multiply and bring both a both b and both can at same place then do sum or subtraction