The factors of
is:
Answers
Answered by
3
Answer:
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
So, if a+b+c=0, a
3
+b
3
+c
3
=3abc
The given expression can be written as
(2a−b)
3
+(b−2c)
3
+(2c−2a)
3
We can see here that 2a−b+b−2c+2c−2a=0.
Hence, following the above concept
(2a−b)
3
+(b−2c)
3
+(2c−2a)
3
=6(2a−b)(b−2c)(c−a)
I hope this thankful
Answered by
3
Step-by-step explanation:
2c-2a or 2(c-a). is right answer
solve it by simple multiply and bring both a both b and both can at same place then do sum or subtraction
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