Question

The factors of the Polynomial 2x²+y²+8z²-2√2xy+4√2yz-8xz

Answer 1

Answer:

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Answer 2

Ans:- 2x²+y²+8z²-2√2xy+4√2yz-8xz

= (√2x)²+(-y)²+(-2√2z)² + 2×(√2x)×(-y) + 2×(-y)×(-2√2z) + 2×(√2x)×(-y)

= (√2x - y - 2√2z)²

= (√2x - y - 2√2z)(√2x - y - 2√2x)

hence (√2x - y - 2√2z) is a factor of 2x²+y²+8z²-2√2xy+4√2yz-8xz

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