Math, asked by rrmehta1983, 4 months ago

the factors of the Quadratic equation y2 -8y-20 = 0​

Answers

Answered by ghatejanhavi74
3

Step-by-step explanation:

The first term is, y2 its coefficient is 1 .

The middle term is, -y its coefficient is -1 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 1 • -2 = -2

Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -1 .

-2 + 1 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 1

y2 - 2y + 1y - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-2)

Add up the last 2 terms, pulling out common factors :

1 • (y-2)

Step-5 : Add up the four terms of step 4 :

(y+1) • (y-2)

Which is the desired factorization

Answered by rameshtakankhar832
1

Step-by-step explanation:

y2+8y-20y=0

y2-10y+2-20=0

y(y-10) +2(y-10)=0

(y-10) - (x+2) =0

x-10=0 or x+2

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