Question

The factors of x ( 12x + 7 ) - 10 is

Answer 1

Answer:

Here Your Answer Mate

Givenpolynomialx(12x+7)−10

Givenpolynomialx(12x+7)−10=12x

Givenpolynomialx(12x+7)−10=12x 2

Givenpolynomialx(12x+7)−10=12x 2 +7x−10

Givenpolynomialx(12x+7)−10=12x 2 +7x−10

Givenpolynomialx(12x+7)−10=12x 2 +7x−10

Givenpolynomialx(12x+7)−10=12x 2 +7x−10 /* Splitting the middle term, we get */

Givenpolynomialx(12x+7)−10=12x 2 +7x−10 /* Splitting the middle term, we get */\begin{gathered}= 12x^{2} +15x - 8x - 10 \\= 3x( 4x + 5 ) - 2( 4x + 5 ) \\= (4x+5)(3x-2)

Givenpolynomialx(12x+7)−10=12x 2 +7x−10 /* Splitting the middle term, we get */\begin{gathered}= 12x^{2} +15x - 8x - 10 \\= 3x( 4x + 5 ) - 2( 4x + 5 ) \\= (4x+5)(3x-2)=12x

Givenpolynomialx(12x+7)−10=12x 2 +7x−10 /* Splitting the middle term, we get */\begin{gathered}= 12x^{2} +15x - 8x - 10 \\= 3x( 4x + 5 ) - 2( 4x + 5 ) \\= (4x+5)(3x-2)=12x 2

Givenpolynomialx(12x+7)−10=12x 2 +7x−10 /* Splitting the middle term, we get */\begin{gathered}= 12x^{2} +15x - 8x - 10 \\= 3x( 4x + 5 ) - 2( 4x + 5 ) \\= (4x+5)(3x-2)=12x 2 \: x(12x+7)-10 } \\\green {= (4x+5)(3x-2)}\end{gathered}

\: x(12x+7)-10 } \\\green {= (4x+5)(3x-2)}\end{gathered} Factorsofx(12x+7)−10

\: x(12x+7)-10 } \\\green {= (4x+5)(3x-2)}\end{gathered} Factorsofx(12x+7)−10=(4x+5)(3x−2)

\: x(12x+7)-10 } \\\green {= (4x+5)(3x-2)}\end{gathered} Factorsofx(12x+7)−10=(4x+5)(3x−2)

Answer 2

$\sf \large \red{\underline{ Question:-}}$

• $\sf \: The \: factors \: of \: x ( 12x + 7 ) - 10 \: is$

$\\\\\sf \large \red{\underline{Given:-}}$

• $\sf \to \: x ( 12x + 7 ) - 10$

$\\\\\sf \large \red{\underline{To \: Find:-}}$

• $\sf \to \: Find \: the \: factor$

$\\\\\sf \large \red{\underline{Solution :- }}$

$\sf \to \: x ( 12x + 7 ) - 10 \\ \\ \sf \to \: {12x}^{2} + 7x - 10 \\ \\ \sf \to \: {12x}^{2} + 15x - 8x - 10 \\ \\ \sf \to \: 3x(4x + 5) - 2(4x + 5) \\ \\ \sf \to (4x + 5)(3x - 2)$

$\sf \underline {\red{ the \: factor \: is }\: (4x + 5)(3x - 2) } \: \huge \: \dag \:$

$\large\underline{ \sf \bigstar \red{ \: {verification : }}}$

$\sf \to \: (4x + 5)(3x - 2) \\ \\ \sf \to \: 12 {x}^{2} - 8x + 15x - 10 \\ \\ \sf \to \: {12x}^{2} + 7x - 10 \: \\ \\ \sf \to x ( 12x + 7 ) - 10$

$\sf \large\red { hence \: verified}\huge \dag \:$