Question

The factors of x^2-x-12 are ?​

Answer 1

Answer:

factors are -3 and 4

${x}^{2} - x - 12 = {x}^{2}+3x - 4x - 12 \\ = x(x+3) - 4(x + 3) \\ = (x+3)(x - 4)$

$(x + 3)(x - 4)= 0 \\(x + 3) = 0 \\ x = - 3 \\ (x - 4) = 0 \\ x = 4$